What are the solutions to the equation 0=3h^2+16h-3584 ?

The solutions to the equation 0=3h^2+16h-3584 are h=32,h=-112/3

Find the zeros of 0=3h^2+16h-3584

The zeros of 0=3h^2+16h-3584 are h=32,h=-112/3

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0 = 3 h^{2} + 16 h - 3584

h = 32, h = - \frac{112}{3}

Decimal Notation

h = 32, h = - 37.33333 \dots

Solution steps

0 = 3 h^{2} + 16 h - 3584

Switch sides

3 h^{2} + 16 h - 3584 = 0

Solve with the quadratic formula

h_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 3 ( - 3584 )}{2 \cdot 3}

1 6^{2} - 4 \cdot 3 (- 3584) = 208

h_{1, 2} = \frac{- 16 \pm 208}{2 \cdot 3}

Separate the solutions

h_{1} = \frac{- 16 + 208}{2 \cdot 3}, h_{2} = \frac{- 16 - 208}{2 \cdot 3}

h = \frac{- 16 + 208}{2 \cdot 3} : 32

h = \frac{- 16 - 208}{2 \cdot 3} : - \frac{112}{3}

The solutions to the quadratic equation are:

h = 32, h = - \frac{112}{3}

\frac{x}{5} - 9 = 3

\frac{19}{x y ^{2}} - \frac{7 y ^{2}}{8 x ^{2}}

k^{2} - 15 k = - 36

e^{- 2 l n (x)}

What are the solutions to the equation 0=3h^2+16h-3584 ?
The solutions to the equation 0=3h^2+16h-3584 are h=32,h=-112/3
Find the zeros of 0=3h^2+16h-3584
The zeros of 0=3h^2+16h-3584 are h=32,h=-112/3