What are the solutions to the equation c^2+9c+10=-2 ?

The solutions to the equation c^2+9c+10=-2 are c=(-9+sqrt(33))/2 ,c=(-9-sqrt(33))/2

Find the zeros of c^2+9c+10=-2

The zeros of c^2+9c+10=-2 are c=(-9+sqrt(33))/2 ,c=(-9-sqrt(33))/2

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c^{2} + 9 c + 10 = - 2

c = \frac{- 9 + 33}{2}, c = \frac{- 9 - 33}{2}

Decimal Notation

c = - 1.62771 \dots, c = - 7.37228 \dots

Solution steps

c^{2} + 9 c + 10 = - 2

Move

2

to the left side

c^{2} + 9 c + 12 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 12}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 12 = 33

c_{1, 2} = \frac{- 9 \pm 33}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 9 + 33}{2 \cdot 1}, c_{2} = \frac{- 9 - 33}{2 \cdot 1}

c = \frac{- 9 + 33}{2 \cdot 1} : \frac{- 9 + 33}{2}

c = \frac{- 9 - 33}{2 \cdot 1} : \frac{- 9 - 33}{2}

The solutions to the quadratic equation are:

c = \frac{- 9 + 33}{2}, c = \frac{- 9 - 33}{2}

3 x - 4 = x + 5

6 x^{2} + 31 x = 17

4 x (x + 5) - 3 (x + 5)

4 q < 8

(7 i)^{2}

What are the solutions to the equation c^2+9c+10=-2 ?
The solutions to the equation c^2+9c+10=-2 are c=(-9+sqrt(33))/2 ,c=(-9-sqrt(33))/2
Find the zeros of c^2+9c+10=-2
The zeros of c^2+9c+10=-2 are c=(-9+sqrt(33))/2 ,c=(-9-sqrt(33))/2