What are the solutions to the equation 3x^2=4x-x^2 ?

The solutions to the equation 3x^2=4x-x^2 are x=0,x=1

Find the zeros of 3x^2=4x-x^2

The zeros of 3x^2=4x-x^2 are x=0,x=1

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3 x^{2} = 4 x - x^{2}

x = 0, x = 1

Solution steps

3 x^{2} = 4 x - x^{2}

Switch sides

4 x - x^{2} = 3 x^{2}

Move

3 x^{2}

to the left side

4 x - 4 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} + 4 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 4 ) \cdot 0}{2 ( - 4 )}

4^{2} - 4 (- 4) \cdot 0 = 4

x_{1, 2} = \frac{- 4 \pm 4}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 4 + 4}{2 ( - 4 )}, x_{2} = \frac{- 4 - 4}{2 ( - 4 )}

x = \frac{- 4 + 4}{2 ( - 4 )} : 0

x = \frac{- 4 - 4}{2 ( - 4 )} : 1

The solutions to the quadratic equation are:

x = 0, x = 1

3 x + 2.4 \geq 3

b^{8} (2 b)^{3}

\frac{2 x + 5}{10} = \frac{42}{20}

3 x + 4 = 6 x + 19

5 x - 6 = 18 + 2 x

What are the solutions to the equation 3x^2=4x-x^2 ?
The solutions to the equation 3x^2=4x-x^2 are x=0,x=1
Find the zeros of 3x^2=4x-x^2
The zeros of 3x^2=4x-x^2 are x=0,x=1