What are the solutions to the equation x^2-15x+22=0 ?

The solutions to the equation x^2-15x+22=0 are x=(15+sqrt(137))/2 ,x=(15-sqrt(137))/2

Find the zeros of x^2-15x+22=0

The zeros of x^2-15x+22=0 are x=(15+sqrt(137))/2 ,x=(15-sqrt(137))/2

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x^{2} - 15 x + 22 = 0

x = \frac{15 + 137}{2}, x = \frac{15 - 137}{2}

Decimal Notation

x = 13.35234 \dots, x = 1.64765 \dots

Solution steps

x^{2} - 15 x + 22 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 22 = 137

x_{1, 2} = \frac{- ( - 15 ) \pm 137}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 137}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 137}{2 \cdot 1}

x = \frac{- ( - 15 ) + 137}{2 \cdot 1} : \frac{15 + 137}{2}

x = \frac{- ( - 15 ) - 137}{2 \cdot 1} : \frac{15 - 137}{2}

The solutions to the quadratic equation are:

x = \frac{15 + 137}{2}, x = \frac{15 - 137}{2}

- \frac{4}{9} r + \frac{3}{4} r - \frac{3}{4} r = - \frac{5}{6}

\frac{12}{7} = 6 y

0.05 x + 0.2 (24 - x) = 0.1 (24)

1 + 4 (8 c - 6) < - 6 c - 10 - 1

2 x^{2} + 2 x < 11 x - 9

What are the solutions to the equation x^2-15x+22=0 ?
The solutions to the equation x^2-15x+22=0 are x=(15+sqrt(137))/2 ,x=(15-sqrt(137))/2
Find the zeros of x^2-15x+22=0
The zeros of x^2-15x+22=0 are x=(15+sqrt(137))/2 ,x=(15-sqrt(137))/2