What is the answer to (x+3)^2+2x=5x+x^2-2 ?

The answer to (x+3)^2+2x=5x+x^2-2 is x=-11/3

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(x+3)^2+2x=5x+x^2-2

(x + 3)^{2} + 2 x = 5 x + x^{2} - 2

x = - \frac{11}{3}

Decimal Notation

x = - 3.66666 \dots

Solution steps

(x + 3)^{2} + 2 x = 5 x + x^{2} - 2

Expand

(x + 3)^{2} + 2 x : x^{2} + 8 x + 9

x^{2} + 8 x + 9 = 5 x + x^{2} - 2

Move

9

to the right side

x^{2} + 8 x = x^{2} + 5 x - 11

Subtract

x^{2} + 5 x

from both sides

x^{2} + 8 x - (x^{2} + 5 x) = x^{2} + 5 x - 11 - (x^{2} + 5 x)

Simplify

3 x = - 11

Divide both sides by

3

x = - \frac{11}{3}

4 + 6

4^{- \frac{1}{2}}

4 x^{2} + 32 = 0

x^{2} + 5 x + 6 > 0

3 (1 - 2 x) > 3 - 6 x

What is the answer to (x+3)^2+2x=5x+x^2-2 ?
The answer to (x+3)^2+2x=5x+x^2-2 is x=-11/3
Solve for x: (x+3)^2+2x=5x+x^2-2
The solution is x=-11/3