What are the solutions to the equation 3x^2-39=0 ?

The solutions to the equation 3x^2-39=0 are x=sqrt(13),x=-sqrt(13)

Find the zeros of 3x^2-39=0

The zeros of 3x^2-39=0 are x=sqrt(13),x=-sqrt(13)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} - 39 = 0

x = 13, x = - 13

Decimal Notation

x = 3.60555 \dots, x = - 3.60555 \dots

Solution steps

3 x^{2} - 39 = 0

Move

39

to the right side

3 x^{2} = 39

Divide both sides by

3

x^{2} = 13

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 13, x = - 13

\frac{2 x}{2} + 4 - 4 x = 6 + 2 x

\frac{( x + 13 ) ( x - 15 )}{x + 11} \leq 0

3 x^{3} + 12 x^{2} + 9 x

16 - 2 t = 5 t + 9

1.0 1^{60}

What are the solutions to the equation 3x^2-39=0 ?
The solutions to the equation 3x^2-39=0 are x=sqrt(13),x=-sqrt(13)
Find the zeros of 3x^2-39=0
The zeros of 3x^2-39=0 are x=sqrt(13),x=-sqrt(13)