What are the solutions to the equation -3=x^2+4x-8 ?

The solutions to the equation -3=x^2+4x-8 are x=1,x=-5

Find the zeros of -3=x^2+4x-8

The zeros of -3=x^2+4x-8 are x=1,x=-5

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- 3 = x^{2} + 4 x - 8

x = 1, x = - 5

Solution steps

- 3 = x^{2} + 4 x - 8

Switch sides

x^{2} + 4 x - 8 = - 3

Move

3

to the left side

x^{2} + 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- 4 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 6}{2 \cdot 1}, x_{2} = \frac{- 4 - 6}{2 \cdot 1}

x = \frac{- 4 + 6}{2 \cdot 1} : 1

x = \frac{- 4 - 6}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

x^{2} + 3 x + 6 = 0

\frac{b ^{- 2}}{a b ^{- 3}}

k^{2} + 4 kn - 96 n^{2}

5 x^{2} - 3 x + 1 = 0

3^{2} + x^{2} = (2 x - 3)^{2}

What are the solutions to the equation -3=x^2+4x-8 ?
The solutions to the equation -3=x^2+4x-8 are x=1,x=-5
Find the zeros of -3=x^2+4x-8
The zeros of -3=x^2+4x-8 are x=1,x=-5