What are the solutions to the equation 3x^2+2x-5=0 ?

The solutions to the equation 3x^2+2x-5=0 are x=1,x=-5/3

Find the zeros of 3x^2+2x-5=0

The zeros of 3x^2+2x-5=0 are x=1,x=-5/3

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3 x^{2} + 2 x - 5 = 0

x = 1, x = - \frac{5}{3}

Decimal Notation

x = 1, x = - 1.66666 \dots

Solution steps

3 x^{2} + 2 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 5) = 8

x_{1, 2} = \frac{- 2 \pm 8}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 8}{2 \cdot 3}, x_{2} = \frac{- 2 - 8}{2 \cdot 3}

x = \frac{- 2 + 8}{2 \cdot 3} : 1

x = \frac{- 2 - 8}{2 \cdot 3} : - \frac{5}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{5}{3}

\frac{1}{6} + 1

(- \frac{3}{4})^{2}

3 a - 28 - 7 a = 10 a

f^{2} + 18 f - 19

\frac{a}{- 3} - 2 = 6

What are the solutions to the equation 3x^2+2x-5=0 ?
The solutions to the equation 3x^2+2x-5=0 are x=1,x=-5/3
Find the zeros of 3x^2+2x-5=0
The zeros of 3x^2+2x-5=0 are x=1,x=-5/3