What are the solutions to the equation x^2-5x-10=0 ?

The solutions to the equation x^2-5x-10=0 are x=(5+sqrt(65))/2 ,x=(5-sqrt(65))/2

Find the zeros of x^2-5x-10=0

The zeros of x^2-5x-10=0 are x=(5+sqrt(65))/2 ,x=(5-sqrt(65))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 5 x - 10 = 0

x = \frac{5 + 65}{2}, x = \frac{5 - 65}{2}

Decimal Notation

x = 6.53112 \dots, x = - 1.53112 \dots

Solution steps

x^{2} - 5 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 10) = 65

x_{1, 2} = \frac{- ( - 5 ) \pm 65}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 65}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 65}{2 \cdot 1}

x = \frac{- ( - 5 ) + 65}{2 \cdot 1} : \frac{5 + 65}{2}

x = \frac{- ( - 5 ) - 65}{2 \cdot 1} : \frac{5 - 65}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 65}{2}, x = \frac{5 - 65}{2}

lo g_{\frac{1}{5}} (x + 1) + lo g_{5} (x + 2) < 1

- 18 x^{2} + 34 x - 23 \leq 0

- 6 (1 - 5 v) = 54

3 x^{2} + 2 x - 5 = 0

\frac{1}{6} + 1

What are the solutions to the equation x^2-5x-10=0 ?
The solutions to the equation x^2-5x-10=0 are x=(5+sqrt(65))/2 ,x=(5-sqrt(65))/2
Find the zeros of x^2-5x-10=0
The zeros of x^2-5x-10=0 are x=(5+sqrt(65))/2 ,x=(5-sqrt(65))/2