What are the solutions to the equation 4n^2+24n+25=4n ?

The solutions to the equation 4n^2+24n+25=4n are n=-5/2

Find the zeros of 4n^2+24n+25=4n

The zeros of 4n^2+24n+25=4n are n=-5/2

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4 n^{2} + 24 n + 25 = 4 n

n = - \frac{5}{2}

Decimal Notation

n = - 2.5

Solution steps

4 n^{2} + 24 n + 25 = 4 n

Move

4 n

to the left side

4 n^{2} + 20 n + 25 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

2 0^{2} - 4 \cdot 4 \cdot 25 = 0

n_{1, 2} = \frac{- 20 \pm 0}{2 \cdot 4}

n = \frac{- 20}{2 \cdot 4}

\frac{- 20}{2 \cdot 4} = - \frac{5}{2}

n = - \frac{5}{2}

The solution to the quadratic equation is:

n = - \frac{5}{2}

25 m^{2} - 16 n^{2}

2 x^{2} + 4 x - 48

18 b - 9 b^{2}

- \frac{1}{4} - (- \frac{3}{5})

Y = - 6 + (- 1)

What are the solutions to the equation 4n^2+24n+25=4n ?
The solutions to the equation 4n^2+24n+25=4n are n=-5/2
Find the zeros of 4n^2+24n+25=4n
The zeros of 4n^2+24n+25=4n are n=-5/2