What are the solutions to the equation -x^2-x=-9 ?

The solutions to the equation -x^2-x=-9 are x=-(1+sqrt(37))/2 ,x=(sqrt(37)-1)/2

Find the zeros of -x^2-x=-9

The zeros of -x^2-x=-9 are x=-(1+sqrt(37))/2 ,x=(sqrt(37)-1)/2

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- x^{2} - x = - 9

x = - \frac{1 + 37}{2}, x = \frac{37 - 1}{2}

Decimal Notation

x = - 3.54138 \dots, x = 2.54138 \dots

Solution steps

- x^{2} - x = - 9

Move

9

to the left side

- x^{2} - x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 ( - 1 ) \cdot 9}{2 ( - 1 )}

(- 1)^{2} - 4 (- 1) \cdot 9 = 37

x_{1, 2} = \frac{- ( - 1 ) \pm 37}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 37}{2 ( - 1 )}, x_{2} = \frac{- ( - 1 ) - 37}{2 ( - 1 )}

x = \frac{- ( - 1 ) + 37}{2 ( - 1 )} : - \frac{1 + 37}{2}

x = \frac{- ( - 1 ) - 37}{2 ( - 1 )} : \frac{37 - 1}{2}

The solutions to the quadratic equation are:

x = - \frac{1 + 37}{2}, x = \frac{37 - 1}{2}

- 4 x + 5 = - 4 x - 4

3 x = - 11

- 15 x^{2} + 6 x + 5 x - 2 \geq 0

5 x^{2} + 13 x + 11 = 5

\frac{1}{\frac{3}{2}}

What are the solutions to the equation -x^2-x=-9 ?
The solutions to the equation -x^2-x=-9 are x=-(1+sqrt(37))/2 ,x=(sqrt(37)-1)/2
Find the zeros of -x^2-x=-9
The zeros of -x^2-x=-9 are x=-(1+sqrt(37))/2 ,x=(sqrt(37)-1)/2