What are the solutions to the equation -6v^2-7v-2=0 ?

The solutions to the equation -6v^2-7v-2=0 are v=-2/3 ,v=-1/2

Find the zeros of -6v^2-7v-2=0

The zeros of -6v^2-7v-2=0 are v=-2/3 ,v=-1/2

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- 6 v^{2} - 7 v - 2 = 0

v = - \frac{2}{3}, v = - \frac{1}{2}

Decimal Notation

v = - 0.66666 \dots, v = - 0.5

Solution steps

- 6 v^{2} - 7 v - 2 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 ( - 6 ) ( - 2 )}{2 ( - 6 )}

(- 7)^{2} - 4 (- 6) (- 2) = 1

v_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 ( - 6 )}

Separate the solutions

v_{1} = \frac{- ( - 7 ) + 1}{2 ( - 6 )}, v_{2} = \frac{- ( - 7 ) - 1}{2 ( - 6 )}

v = \frac{- ( - 7 ) + 1}{2 ( - 6 )} : - \frac{2}{3}

v = \frac{- ( - 7 ) - 1}{2 ( - 6 )} : - \frac{1}{2}

The solutions to the quadratic equation are:

v = - \frac{2}{3}, v = - \frac{1}{2}

\frac{6}{1 + 2}

∣ 5 ∣ - 7

a^{2} = 289

∣ 4 x - 6 ∣ + 2 \geq 7

27 x^{3} + 8 y^{3}

What are the solutions to the equation -6v^2-7v-2=0 ?
The solutions to the equation -6v^2-7v-2=0 are v=-2/3 ,v=-1/2
Find the zeros of -6v^2-7v-2=0
The zeros of -6v^2-7v-2=0 are v=-2/3 ,v=-1/2