What are the solutions to the equation 3x^2-4x+6=0 ?

The solutions to the equation 3x^2-4x+6=0 are x= 2/3+i(sqrt(14))/3 ,x= 2/3-i(sqrt(14))/3

Find the zeros of 3x^2-4x+6=0

The zeros of 3x^2-4x+6=0 are x= 2/3+i(sqrt(14))/3 ,x= 2/3-i(sqrt(14))/3

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3 x^{2} - 4 x + 6 = 0

x = \frac{2}{3} + i \frac{14}{3}, x = \frac{2}{3} - i \frac{14}{3}

Solution steps

3 x^{2} - 4 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

Simplify

(- 4)^{2} - 4 \cdot 3 \cdot 6 : 214 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 14 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 14 i}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 2 14 i}{2 \cdot 3}

x = \frac{- ( - 4 ) + 2 14 i}{2 \cdot 3} : \frac{2}{3} + i \frac{14}{3}

x = \frac{- ( - 4 ) - 2 14 i}{2 \cdot 3} : \frac{2}{3} - i \frac{14}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} + i \frac{14}{3}, x = \frac{2}{3} - i \frac{14}{3}

9 x^{2} + 9 x - 40

3 x^{2} + 2 = - x

8 x^{2} - 6 x - 2 = 4

x^{2} - 2 x - 8

lo g_{\frac{1}{3}} (p) < 0

What are the solutions to the equation 3x^2-4x+6=0 ?
The solutions to the equation 3x^2-4x+6=0 are x= 2/3+i(sqrt(14))/3 ,x= 2/3-i(sqrt(14))/3
Find the zeros of 3x^2-4x+6=0
The zeros of 3x^2-4x+6=0 are x= 2/3+i(sqrt(14))/3 ,x= 2/3-i(sqrt(14))/3