What are the solutions to the equation x^2+x=-x-1 ?

The solutions to the equation x^2+x=-x-1 are x=-1

Find the zeros of x^2+x=-x-1

The zeros of x^2+x=-x-1 are x=-1

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x^{2} + x = - x - 1

x = - 1

Solution steps

x^{2} + x = - x - 1

Move

1

to the left side

x^{2} + x + 1 = - x

Move

x

to the left side

x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

x = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

9 x^{2} - 9 x - 28

3 x^{2} + 13 x - 30 = 0

\frac{( 5 - i )}{( 3 + 2 i )}

\frac{2 x ^{3} y ^{4} z ^{7}}{x ^{2} y ^{5} z ^{10}}

2 (b - 4) > - 6

What are the solutions to the equation x^2+x=-x-1 ?
The solutions to the equation x^2+x=-x-1 are x=-1
Find the zeros of x^2+x=-x-1
The zeros of x^2+x=-x-1 are x=-1