What are the solutions to the equation x^2-10x=-35 ?

The solutions to the equation x^2-10x=-35 are x=5+sqrt(10)i,x=5-sqrt(10)i

Find the zeros of x^2-10x=-35

The zeros of x^2-10x=-35 are x=5+sqrt(10)i,x=5-sqrt(10)i

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x^{2} - 10 x = - 35

x = 5 + 10 i, x = 5 - 10 i

Solution steps

x^{2} - 10 x = - 35

Move

35

to the left side

x^{2} - 10 x + 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 35}{2 \cdot 1}

Simplify

(- 10)^{2} - 4 \cdot 1 \cdot 35 : 210 i

x_{1, 2} = \frac{- ( - 10 ) \pm 2 10 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 10 i}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 2 10 i}{2 \cdot 1}

x = \frac{- ( - 10 ) + 2 10 i}{2 \cdot 1} : 5 + 10 i

x = \frac{- ( - 10 ) - 2 10 i}{2 \cdot 1} : 5 - 10 i

The solutions to the quadratic equation are:

x = 5 + 10 i, x = 5 - 10 i

\frac{2}{3} t = \frac{5}{2}

1 6^{2} + 1 6^{2}

- 3 p^{2} + 17 p = 20

\frac{( 1 - 3 i ) ^{2}}{i - 1}

3 2^{- \frac{3}{5}}

What are the solutions to the equation x^2-10x=-35 ?
The solutions to the equation x^2-10x=-35 are x=5+sqrt(10)i,x=5-sqrt(10)i
Find the zeros of x^2-10x=-35
The zeros of x^2-10x=-35 are x=5+sqrt(10)i,x=5-sqrt(10)i