What are the solutions to the equation m^2+18m-3=0 ?

The solutions to the equation m^2+18m-3=0 are m=-9+2sqrt(21),m=-9-2sqrt(21)

Find the zeros of m^2+18m-3=0

The zeros of m^2+18m-3=0 are m=-9+2sqrt(21),m=-9-2sqrt(21)

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m^{2} + 18 m - 3 = 0

m = - 9 + 221, m = - 9 - 221

Decimal Notation

m = 0.16515 \dots, m = - 18.16515 \dots

Solution steps

m^{2} + 18 m - 3 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot (- 3) = 421

m_{1, 2} = \frac{- 18 \pm 4 21}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 18 + 4 21}{2 \cdot 1}, m_{2} = \frac{- 18 - 4 21}{2 \cdot 1}

m = \frac{- 18 + 4 21}{2 \cdot 1} : - 9 + 221

m = \frac{- 18 - 4 21}{2 \cdot 1} : - 9 - 221

The solutions to the quadratic equation are:

m = - 9 + 221, m = - 9 - 221

ln (9) - ln (3)

(8 m + 12)^{2} = 4

0 = 2 x^{2} + 5 x + 6

x^{2} + 80 = - 16 x

\frac{2 3}{12}

What are the solutions to the equation m^2+18m-3=0 ?
The solutions to the equation m^2+18m-3=0 are m=-9+2sqrt(21),m=-9-2sqrt(21)
Find the zeros of m^2+18m-3=0
The zeros of m^2+18m-3=0 are m=-9+2sqrt(21),m=-9-2sqrt(21)