What are the solutions to the equation 6x^2+12x-3=0 ?

The solutions to the equation 6x^2+12x-3=0 are x=(-2+sqrt(6))/2 ,x=-(2+sqrt(6))/2

Find the zeros of 6x^2+12x-3=0

The zeros of 6x^2+12x-3=0 are x=(-2+sqrt(6))/2 ,x=-(2+sqrt(6))/2

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6 x^{2} + 12 x - 3 = 0

x = \frac{- 2 + 6}{2}, x = - \frac{2 + 6}{2}

Decimal Notation

x = 0.22474 \dots, x = - 2.22474 \dots

Solution steps

6 x^{2} + 12 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 ( - 3 )}{2 \cdot 6}

1 2^{2} - 4 \cdot 6 (- 3) = 66

x_{1, 2} = \frac{- 12 \pm 6 6}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 12 + 6 6}{2 \cdot 6}, x_{2} = \frac{- 12 - 6 6}{2 \cdot 6}

x = \frac{- 12 + 6 6}{2 \cdot 6} : \frac{- 2 + 6}{2}

x = \frac{- 12 - 6 6}{2 \cdot 6} : - \frac{2 + 6}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 6}{2}, x = - \frac{2 + 6}{2}

2 x + 3 = 4 x - 1

x^{2} - 9 = 4 x

∣ 2 x - 4 ∣ \leq 8

\frac{3}{2} x - 2 + 1 \leq 2

- 1 - \frac{4}{3}

What are the solutions to the equation 6x^2+12x-3=0 ?
The solutions to the equation 6x^2+12x-3=0 are x=(-2+sqrt(6))/2 ,x=-(2+sqrt(6))/2
Find the zeros of 6x^2+12x-3=0
The zeros of 6x^2+12x-3=0 are x=(-2+sqrt(6))/2 ,x=-(2+sqrt(6))/2