What is (80x^4)/(y^3)*(xy)/(5x^2) ?

The solution to (80x^4)/(y^3)*(xy)/(5x^2) is (16x^3)/(y^2)

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simplify (80x^4)/(y^3)*(xy)/(5x^2)

simplify

\frac{80 x ^{4}}{y ^{3}} \cdot \frac{x y}{5 x ^{2}}

\frac{16 x ^{3}}{y ^{2}}

Solution steps

\frac{80 x ^{4}}{y ^{3}} \cdot \frac{x y}{5 x ^{2}}

Cancel

\frac{x y}{5 x ^{2}} : \frac{y}{5 x}

= \frac{80 x ^{4}}{y ^{3}} \cdot \frac{y}{5 x}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{80 x ^{4} y}{y ^{3} \cdot 5 x}

Factor the number:

80 = 5 \cdot 16

= \frac{5 \cdot 16 x ^{4} y}{y ^{3} \cdot 5 x}

Cancel the common factor:

5

= \frac{16 x ^{4} y}{y ^{3} x}

Simplify

\frac{x ^{4}}{x} : x^{3}

= \frac{16 x ^{3} y}{y ^{3}}

Simplify

\frac{y}{y ^{3}} : \frac{1}{y ^{2}}

= \frac{16 x ^{3}}{y ^{2}}

6 x^{2} - 96

4 x^{2} - 8 x - 60 = 0

3 d^{2} = - 15

x^{\frac{5}{2}} - 4 x^{\frac{1}{2}}

(1 + i 3)^{3}

What is (80x^4)/(y^3)*(xy)/(5x^2) ?
The solution to (80x^4)/(y^3)*(xy)/(5x^2) is (16x^3)/(y^2)