What are the solutions to the equation 4X^2-4X-8=-9 ?

The solutions to the equation 4X^2-4X-8=-9 are X= 1/2

Find the zeros of 4X^2-4X-8=-9

The zeros of 4X^2-4X-8=-9 are X= 1/2

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4 X^{2} - 4 X - 8 = - 9

X = \frac{1}{2}

Decimal Notation

X = 0.5

Solution steps

4 X^{2} - 4 X - 8 = - 9

Move

9

to the left side

4 X^{2} - 4 X + 1 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 4)^{2} - 4 \cdot 4 \cdot 1 = 0

X_{1, 2} = \frac{- ( - 4 ) \pm 0}{2 \cdot 4}

X = \frac{- ( - 4 )}{2 \cdot 4}

\frac{- ( - 4 )}{2 \cdot 4} = \frac{1}{2}

X = \frac{1}{2}

The solution to the quadratic equation is:

X = \frac{1}{2}

(3 x + 2)^{2} = (x + 2) (x - 3)

- 2 x + 12 < 48

x - 17 = 23

\frac{13}{52} \cdot \frac{13}{52}

(3 x + 2)^{2} - 12 = 0

What are the solutions to the equation 4X^2-4X-8=-9 ?
The solutions to the equation 4X^2-4X-8=-9 are X= 1/2
Find the zeros of 4X^2-4X-8=-9
The zeros of 4X^2-4X-8=-9 are X= 1/2