What are the solutions to the equation (x-10)(x-6)=-4 ?

The solutions to the equation (x-10)(x-6)=-4 are x=8

Find the zeros of (x-10)(x-6)=-4

The zeros of (x-10)(x-6)=-4 are x=8

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(x - 10) (x - 6) = - 4

x = 8

Solution steps

(x - 10) (x - 6) = - 4

Expand

(x - 10) (x - 6) : x^{2} - 16 x + 60

x^{2} - 16 x + 60 = - 4

Move

4

to the left side

x^{2} - 16 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 64 = 0

x_{1, 2} = \frac{- ( - 16 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 16 )}{2 \cdot 1}

\frac{- ( - 16 )}{2 \cdot 1} = 8

x = 8

The solution to the quadratic equation is:

x = 8

- 4 c^{2} + 19 c + 5

x^{2} + 13 x + 22 = 7

\frac{17}{17}

\frac{1}{8} + \frac{3}{16}

(\frac{5}{7})^{2}

What are the solutions to the equation (x-10)(x-6)=-4 ?
The solutions to the equation (x-10)(x-6)=-4 are x=8
Find the zeros of (x-10)(x-6)=-4
The zeros of (x-10)(x-6)=-4 are x=8