What are the solutions to the equation 6q^2+3q=5q^2-2q+14 ?

The solutions to the equation 6q^2+3q=5q^2-2q+14 are q=-7,q=2

Find the zeros of 6q^2+3q=5q^2-2q+14

The zeros of 6q^2+3q=5q^2-2q+14 are q=-7,q=2

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6 q^{2} + 3 q = 5 q^{2} - 2 q + 14

q = - 7, q = 2

Solution steps

6 q^{2} + 3 q = 5 q^{2} - 2 q + 14

Switch sides

5 q^{2} - 2 q + 14 = 6 q^{2} + 3 q

Move

3 q

to the left side

5 q^{2} - 5 q + 14 = 6 q^{2}

Move

6 q^{2}

to the left side

- q^{2} - 5 q + 14 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 ( - 1 ) \cdot 14}{2 ( - 1 )}

(- 5)^{2} - 4 (- 1) \cdot 14 = 9

q_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 ( - 1 )}

Separate the solutions

q_{1} = \frac{- ( - 5 ) + 9}{2 ( - 1 )}, q_{2} = \frac{- ( - 5 ) - 9}{2 ( - 1 )}

q = \frac{- ( - 5 ) + 9}{2 ( - 1 )} : - 7

q = \frac{- ( - 5 ) - 9}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

q = - 7, q = 2

f^{3} + 4 f^{2} + f + 4

- (6 x - 5) = - 6 x + 13

4 x^{2} - 12 x = 7

\frac{8}{2} \cdot 3

5 x^{2} - 36 x - 81

What are the solutions to the equation 6q^2+3q=5q^2-2q+14 ?
The solutions to the equation 6q^2+3q=5q^2-2q+14 are q=-7,q=2
Find the zeros of 6q^2+3q=5q^2-2q+14
The zeros of 6q^2+3q=5q^2-2q+14 are q=-7,q=2