What are the solutions to the equation 2-2x^2+8x=7 ?

The solutions to the equation 2-2x^2+8x=7 are x=(4-sqrt(6))/2 ,x=(4+sqrt(6))/2

Find the zeros of 2-2x^2+8x=7

The zeros of 2-2x^2+8x=7 are x=(4-sqrt(6))/2 ,x=(4+sqrt(6))/2

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2 - 2 x^{2} + 8 x = 7

x = \frac{4 - 6}{2}, x = \frac{4 + 6}{2}

Decimal Notation

x = 0.77525 \dots, x = 3.22474 \dots

Solution steps

2 - 2 x^{2} + 8 x = 7

Move

7

to the left side

- 2 x^{2} + 8 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 2 ) ( - 5 )}{2 ( - 2 )}

8^{2} - 4 (- 2) (- 5) = 26

x_{1, 2} = \frac{- 8 \pm 2 6}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 8 + 2 6}{2 ( - 2 )}, x_{2} = \frac{- 8 - 2 6}{2 ( - 2 )}

x = \frac{- 8 + 2 6}{2 ( - 2 )} : \frac{4 - 6}{2}

x = \frac{- 8 - 2 6}{2 ( - 2 )} : \frac{4 + 6}{2}

The solutions to the quadratic equation are:

x = \frac{4 - 6}{2}, x = \frac{4 + 6}{2}

k = 6 (- 5) + 100

2 x^{2} - 7 x + 1 = 0

lo g_{10} (3 x) < lo g_{10} (7 x - 8)

\frac{1}{4} + \frac{1}{20}

6 q^{2} - 3 q = 5 q^{2} - 8 q + 24

What are the solutions to the equation 2-2x^2+8x=7 ?
The solutions to the equation 2-2x^2+8x=7 are x=(4-sqrt(6))/2 ,x=(4+sqrt(6))/2
Find the zeros of 2-2x^2+8x=7
The zeros of 2-2x^2+8x=7 are x=(4-sqrt(6))/2 ,x=(4+sqrt(6))/2