What are the solutions to the equation 3x^2-7x+9=0 ?

The solutions to the equation 3x^2-7x+9=0 are x= 7/6+i(sqrt(59))/6 ,x= 7/6-i(sqrt(59))/6

Find the zeros of 3x^2-7x+9=0

The zeros of 3x^2-7x+9=0 are x= 7/6+i(sqrt(59))/6 ,x= 7/6-i(sqrt(59))/6

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3 x^{2} - 7 x + 9 = 0

x = \frac{7}{6} + i \frac{59}{6}, x = \frac{7}{6} - i \frac{59}{6}

Solution steps

3 x^{2} - 7 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 9}{2 \cdot 3}

Simplify

(- 7)^{2} - 4 \cdot 3 \cdot 9 : 59 i

x_{1, 2} = \frac{- ( - 7 ) \pm 59 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 59 i}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 59 i}{2 \cdot 3}

x = \frac{- ( - 7 ) + 59 i}{2 \cdot 3} : \frac{7}{6} + i \frac{59}{6}

x = \frac{- ( - 7 ) - 59 i}{2 \cdot 3} : \frac{7}{6} - i \frac{59}{6}

The solutions to the quadratic equation are:

x = \frac{7}{6} + i \frac{59}{6}, x = \frac{7}{6} - i \frac{59}{6}

\frac{1}{4} \cdot \frac{1}{8}

\frac{1}{2} x^{2} + 3 x - 1 = 0

2 x - 7 = 5 x - 19

4 + \frac{5}{4}

\frac{3 ^{a}}{9}

What are the solutions to the equation 3x^2-7x+9=0 ?
The solutions to the equation 3x^2-7x+9=0 are x= 7/6+i(sqrt(59))/6 ,x= 7/6-i(sqrt(59))/6
Find the zeros of 3x^2-7x+9=0
The zeros of 3x^2-7x+9=0 are x= 7/6+i(sqrt(59))/6 ,x= 7/6-i(sqrt(59))/6