What are the solutions to the equation 3x^2+2x+7=0 ?

The solutions to the equation 3x^2+2x+7=0 are x=-1/3+i(2sqrt(5))/3 ,x=-1/3-i(2sqrt(5))/3

Find the zeros of 3x^2+2x+7=0

The zeros of 3x^2+2x+7=0 are x=-1/3+i(2sqrt(5))/3 ,x=-1/3-i(2sqrt(5))/3

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3 x^{2} + 2 x + 7 = 0

x = - \frac{1}{3} + i \frac{2 5}{3}, x = - \frac{1}{3} - i \frac{2 5}{3}

Solution steps

3 x^{2} + 2 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

Simplify

2^{2} - 4 \cdot 3 \cdot 7 : 45 i

x_{1, 2} = \frac{- 2 \pm 4 5 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 4 5 i}{2 \cdot 3}, x_{2} = \frac{- 2 - 4 5 i}{2 \cdot 3}

x = \frac{- 2 + 4 5 i}{2 \cdot 3} : - \frac{1}{3} + i \frac{2 5}{3}

x = \frac{- 2 - 4 5 i}{2 \cdot 3} : - \frac{1}{3} - i \frac{2 5}{3}

The solutions to the quadratic equation are:

x = - \frac{1}{3} + i \frac{2 5}{3}, x = - \frac{1}{3} - i \frac{2 5}{3}

2 y - 1 > - 3 or - 4 y > 24

(2 x - 9)^{2} = 12

- \frac{1}{5} p + \frac{9}{5} p + 6 = 30

2180

4 a^{4} b - 6 a^{2} b^{2} + 12 a^{3} b

What are the solutions to the equation 3x^2+2x+7=0 ?
The solutions to the equation 3x^2+2x+7=0 are x=-1/3+i(2sqrt(5))/3 ,x=-1/3-i(2sqrt(5))/3
Find the zeros of 3x^2+2x+7=0
The zeros of 3x^2+2x+7=0 are x=-1/3+i(2sqrt(5))/3 ,x=-1/3-i(2sqrt(5))/3