What are the solutions to the equation x^2+64=25 ?

The solutions to the equation x^2+64=25 are x=sqrt(39)i,x=-sqrt(39)i

Find the zeros of x^2+64=25

The zeros of x^2+64=25 are x=sqrt(39)i,x=-sqrt(39)i

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x^{2} + 64 = 25

x = 39 i, x = - 39 i

Solution steps

x^{2} + 64 = 25

Move

64

to the right side

x^{2} = - 39

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 39, x = - - 39

- 39 = 39 i

- - 39 = - 39 i

x = 39 i, x = - 39 i

\frac{\frac{5}{2}}{3}

4 (x + 8) - 9 > 31

\frac{4}{5} x \geq 8

(\frac{2}{3})^{\frac{3}{2}}

346

What are the solutions to the equation x^2+64=25 ?
The solutions to the equation x^2+64=25 are x=sqrt(39)i,x=-sqrt(39)i
Find the zeros of x^2+64=25
The zeros of x^2+64=25 are x=sqrt(39)i,x=-sqrt(39)i