What are the solutions to the equation p^2-p=0 ?

The solutions to the equation p^2-p=0 are p=1,p=0

Find the zeros of p^2-p=0

The zeros of p^2-p=0 are p=1,p=0

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p^{2} - p = 0

p = 1, p = 0

Solution steps

p^{2} - p = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot 0 = 1

p_{1, 2} = \frac{- ( - 1 ) \pm 1}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 1 ) + 1}{2 \cdot 1}, p_{2} = \frac{- ( - 1 ) - 1}{2 \cdot 1}

p = \frac{- ( - 1 ) + 1}{2 \cdot 1} : 1

p = \frac{- ( - 1 ) - 1}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

p = 1, p = 0

11 \cdot 9.8

7 - \frac{x}{5} = - 1

2 x^{2} - 3 x + 17 = 0

∣ x + 8 ∣ \leq 11

- 7 + \frac{x}{3} > - 4

What are the solutions to the equation p^2-p=0 ?
The solutions to the equation p^2-p=0 are p=1,p=0
Find the zeros of p^2-p=0
The zeros of p^2-p=0 are p=1,p=0