What are the solutions to the equation 5x^2+3x-5=0 ?

The solutions to the equation 5x^2+3x-5=0 are x=(-3+sqrt(109))/(10),x=(-3-sqrt(109))/(10)

Find the zeros of 5x^2+3x-5=0

The zeros of 5x^2+3x-5=0 are x=(-3+sqrt(109))/(10),x=(-3-sqrt(109))/(10)

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5 x^{2} + 3 x - 5 = 0

x = \frac{- 3 + 109}{10}, x = \frac{- 3 - 109}{10}

Decimal Notation

x = 0.74403 \dots, x = - 1.34403 \dots

Solution steps

5 x^{2} + 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 5 ( - 5 )}{2 \cdot 5}

3^{2} - 4 \cdot 5 (- 5) = 109

x_{1, 2} = \frac{- 3 \pm 109}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 3 + 109}{2 \cdot 5}, x_{2} = \frac{- 3 - 109}{2 \cdot 5}

x = \frac{- 3 + 109}{2 \cdot 5} : \frac{- 3 + 109}{10}

x = \frac{- 3 - 109}{2 \cdot 5} : \frac{- 3 - 109}{10}

The solutions to the quadratic equation are:

x = \frac{- 3 + 109}{10}, x = \frac{- 3 - 109}{10}

(x + 2) (x + 2) = 0

5 b^{2} + 21 b + 4

9^{\frac{5}{2}}

(f^{- 3} g^{5} h^{8})^{- 3}

\frac{( - 6 ) - 4}{( - 6 ) ^{2} - 16}

What are the solutions to the equation 5x^2+3x-5=0 ?
The solutions to the equation 5x^2+3x-5=0 are x=(-3+sqrt(109))/(10),x=(-3-sqrt(109))/(10)
Find the zeros of 5x^2+3x-5=0
The zeros of 5x^2+3x-5=0 are x=(-3+sqrt(109))/(10),x=(-3-sqrt(109))/(10)