What are the solutions to the equation y^2+6y-40=0 ?

The solutions to the equation y^2+6y-40=0 are y=4,y=-10

Find the zeros of y^2+6y-40=0

The zeros of y^2+6y-40=0 are y=4,y=-10

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y^{2} + 6 y - 40 = 0

y = 4, y = - 10

Solution steps

y^{2} + 6 y - 40 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 40) = 14

y_{1, 2} = \frac{- 6 \pm 14}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 6 + 14}{2 \cdot 1}, y_{2} = \frac{- 6 - 14}{2 \cdot 1}

y = \frac{- 6 + 14}{2 \cdot 1} : 4

y = \frac{- 6 - 14}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

y = 4, y = - 10

10 x^{2} - 17 x + 3 = 0

\frac{( x - 9 )}{( x - 2 )} > 0

∣ 7 x ∣ \geq 14

∣ x + 1 ∣ + ∣ x - 4 ∣ + ∣ x - 5 ∣ = 26

(- 4 x)^{3}

What are the solutions to the equation y^2+6y-40=0 ?
The solutions to the equation y^2+6y-40=0 are y=4,y=-10
Find the zeros of y^2+6y-40=0
The zeros of y^2+6y-40=0 are y=4,y=-10