What is (b^2-2b-8)/(b^2+b-2)-6/(b-1) ?

The solution to (b^2-2b-8)/(b^2+b-2)-6/(b-1) is (b-10)/(b-1)

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simplify (b^2-2b-8)/(b^2+b-2)-6/(b-1)

simplify

\frac{b ^{2} - 2 b - 8}{b ^{2} + b - 2} - \frac{6}{b - 1}

\frac{b - 10}{b - 1}

Solution steps

\frac{b ^{2} - 2 b - 8}{b ^{2} + b - 2} - \frac{6}{b - 1}

Cancel

\frac{b ^{2} - 2 b - 8}{b ^{2} + b - 2} : \frac{b - 4}{b - 1}

= \frac{b - 4}{b - 1} - \frac{6}{b - 1}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{b - 4 - 6}{b - 1}

Subtract the numbers:

- 4 - 6 = - 10

= \frac{b - 10}{b - 1}

5 \cdot 4

32 - 50

5 x - 8 = 3 x - 9

3 y + 4 (y + 3) - 5 (1 - 2 y) = 1 - 4 (5 y - 2) - 4 y - 1

98 - 2 y^{4}

What is (b^2-2b-8)/(b^2+b-2)-6/(b-1) ?
The solution to (b^2-2b-8)/(b^2+b-2)-6/(b-1) is (b-10)/(b-1)