What is factor 64x^2+16x+1 ?

The solution to factor 64x^2+16x+1 is (8x+1)^2

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factor 64x^2+16x+1

factor

64 x^{2} + 16 x + 1

(8 x + 1)^{2}

Solution steps

64 x^{2} + 16 x + 1

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

64 x^{2} = (8 x)^{2}

1 = 1^{2}

16 x = 2 \cdot 8 x \cdot 1

= (8 x)^{2} + 2 \cdot 8 x \cdot 1 + 1^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(8 x)^{2} + 2 \cdot 8 x \cdot 1 + 1^{2} = (8 x + 1)^{2}

= (8 x + 1)^{2}

\frac{2 - 2 i ^{3}}{3 - i ^{5}} + \frac{- 2 i}{1 - i}

(2 x + 2)^{2} + (4 x)^{2} < (5 x + 1)^{2}

6 (n + 3) + 2 > 3 (n + 2) + 6

0.4 r - 0.13 - 0.7 r = 3 r - 5.74

5 (x^{2} - 2) - 5 = 5