What are the solutions to the equation -6x^2+3x+13=-2x^2 ?

The solutions to the equation -6x^2+3x+13=-2x^2 are x=-(-3+sqrt(217))/8 ,x=(3+sqrt(217))/8

Find the zeros of -6x^2+3x+13=-2x^2

The zeros of -6x^2+3x+13=-2x^2 are x=-(-3+sqrt(217))/8 ,x=(3+sqrt(217))/8

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- 6 x^{2} + 3 x + 13 = - 2 x^{2}

x = - \frac{- 3 + 217}{8}, x = \frac{3 + 217}{8}

Decimal Notation

x = - 1.46636 \dots, x = 2.21636 \dots

Solution steps

- 6 x^{2} + 3 x + 13 = - 2 x^{2}

Move

2 x^{2}

to the left side

- 4 x^{2} + 3 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 4 ) \cdot 13}{2 ( - 4 )}

3^{2} - 4 (- 4) \cdot 13 = 217

x_{1, 2} = \frac{- 3 \pm 217}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 3 + 217}{2 ( - 4 )}, x_{2} = \frac{- 3 - 217}{2 ( - 4 )}

x = \frac{- 3 + 217}{2 ( - 4 )} : - \frac{- 3 + 217}{8}

x = \frac{- 3 - 217}{2 ( - 4 )} : \frac{3 + 217}{8}

The solutions to the quadratic equation are:

x = - \frac{- 3 + 217}{8}, x = \frac{3 + 217}{8}

(\frac{- 3}{2})^{2}

13 x + 26 = 234

\frac{6 x ^{2} - x - 1}{4 x - 2}

{x + 1} \geq 1

x^{2} - 4 x = 6

What are the solutions to the equation -6x^2+3x+13=-2x^2 ?
The solutions to the equation -6x^2+3x+13=-2x^2 are x=-(-3+sqrt(217))/8 ,x=(3+sqrt(217))/8
Find the zeros of -6x^2+3x+13=-2x^2
The zeros of -6x^2+3x+13=-2x^2 are x=-(-3+sqrt(217))/8 ,x=(3+sqrt(217))/8