What is 4{x-(3x-2)}>3(x+5)-15 ?

The solution to 4{x-(3x-2)}>3(x+5)-15 is x< 8/11

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4{x-(3x-2)}>3(x+5)-15

4 {x - (3 x - 2)} > 3 (x + 5) - 15

x < \frac{8}{11}

Interval Notation

(- \infty, \frac{8}{11})

Decimal Notation

x < 0.72727 \dots

Solution steps

4 {x - (3 x - 2)} > 3 (x + 5) - 15

Rewrite in standard form

- 11 x + 8 > 0

Move

8

to the right side

- 11 x > - 8

Multiply both sides by

- 1

11 x < 8

Divide both sides by

11

x < \frac{8}{11}

8 x^{2} + 21 = - 59 x

- x^{2} - 5 x + 6 = 0

\frac{( - 2 ) ^{8} \cdot 5 ^{3}}{5 ^{4} \cdot 2 ^{10} \cdot 10}

(2 x^{\frac{1}{4}})^{4}

- 2 (y - 3) \leq 10

What is 4{x-(3x-2)}>3(x+5)-15 ?
The solution to 4{x-(3x-2)}>3(x+5)-15 is x< 8/11