What are the solutions to the equation 4x^2=32x ?

The solutions to the equation 4x^2=32x are x=0,x=8

Find the zeros of 4x^2=32x

The zeros of 4x^2=32x are x=0,x=8

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4 x^{2} = 32 x

x = 0, x = 8

Solution steps

4 x^{2} = 32 x

Move

32 x

to the left side

4 x^{2} - 32 x = 0

Factor

4 x^{2} - 32 x : 4 x (x - 8)

4 x (x - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 8 = 0

Solve

x - 8 = 0 : x = 8

The solutions to the quadratic equation are:

x = 0, x = 8

10 b + 3 b - 5 = 20

x - 8 = \frac{x}{2} - \frac{x - 6}{3}

\frac{3 h ^{9}}{- 192 h ^{6}}

5 - \frac{3 x}{4} = \frac{2 x}{3} + 22

49 - 14 x + x^{2}

What are the solutions to the equation 4x^2=32x ?
The solutions to the equation 4x^2=32x are x=0,x=8
Find the zeros of 4x^2=32x
The zeros of 4x^2=32x are x=0,x=8