What are the solutions to the equation 4x^2-13x+10=0 ?

The solutions to the equation 4x^2-13x+10=0 are x=2,x= 5/4

Find the zeros of 4x^2-13x+10=0

The zeros of 4x^2-13x+10=0 are x=2,x= 5/4

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4 x^{2} - 13 x + 10 = 0

x = 2, x = \frac{5}{4}

Decimal Notation

x = 2, x = 1.25

Solution steps

4 x^{2} - 13 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 4 \cdot 10}{2 \cdot 4}

(- 13)^{2} - 4 \cdot 4 \cdot 10 = 3

x_{1, 2} = \frac{- ( - 13 ) \pm 3}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 3}{2 \cdot 4}, x_{2} = \frac{- ( - 13 ) - 3}{2 \cdot 4}

x = \frac{- ( - 13 ) + 3}{2 \cdot 4} : 2

x = \frac{- ( - 13 ) - 3}{2 \cdot 4} : \frac{5}{4}

The solutions to the quadratic equation are:

x = 2, x = \frac{5}{4}

3^{2} + b^{2} = 5^{2}

(1 + \frac{0.12}{12})^{12} - 1

14 m^{2} + 17 m - 22

\frac{x - 1}{2} + \frac{2 x + 3}{4} = 1

\frac{4}{9} \cdot \frac{3}{7} \cdot \frac{5}{2}

What are the solutions to the equation 4x^2-13x+10=0 ?
The solutions to the equation 4x^2-13x+10=0 are x=2,x= 5/4
Find the zeros of 4x^2-13x+10=0
The zeros of 4x^2-13x+10=0 are x=2,x= 5/4