What are the solutions to the equation n^2-10n-11=0 ?

The solutions to the equation n^2-10n-11=0 are n=11,n=-1

Find the zeros of n^2-10n-11=0

The zeros of n^2-10n-11=0 are n=11,n=-1

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n^{2} - 10 n - 11 = 0

n = 11, n = - 1

Solution steps

n^{2} - 10 n - 11 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot (- 11) = 12

n_{1, 2} = \frac{- ( - 10 ) \pm 12}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 10 ) + 12}{2 \cdot 1}, n_{2} = \frac{- ( - 10 ) - 12}{2 \cdot 1}

n = \frac{- ( - 10 ) + 12}{2 \cdot 1} : 11

n = \frac{- ( - 10 ) - 12}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

n = 11, n = - 1

\frac{1}{2} - 10

4 x^{2} + 2 x - 20

(\frac{3 ^{4}}{7 ^{3}})^{3}

\frac{2}{5} = \frac{x}{40}

- 2 x > - 12

What are the solutions to the equation n^2-10n-11=0 ?
The solutions to the equation n^2-10n-11=0 are n=11,n=-1
Find the zeros of n^2-10n-11=0
The zeros of n^2-10n-11=0 are n=11,n=-1