What are the solutions to the equation (x+8)(x-9)=4 ?

The solutions to the equation (x+8)(x-9)=4 are x=(1+sqrt(305))/2 ,x=(1-sqrt(305))/2

Find the zeros of (x+8)(x-9)=4

The zeros of (x+8)(x-9)=4 are x=(1+sqrt(305))/2 ,x=(1-sqrt(305))/2

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(x + 8) (x - 9) = 4

x = \frac{1 + 305}{2}, x = \frac{1 - 305}{2}

Decimal Notation

x = 9.23212 \dots, x = - 8.23212 \dots

Solution steps

(x + 8) (x - 9) = 4

Expand

(x + 8) (x - 9) : x^{2} - x - 72

x^{2} - x - 72 = 4

Move

4

to the left side

x^{2} - x - 76 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 76 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 76) = 305

x_{1, 2} = \frac{- ( - 1 ) \pm 305}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 305}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 305}{2 \cdot 1}

x = \frac{- ( - 1 ) + 305}{2 \cdot 1} : \frac{1 + 305}{2}

x = \frac{- ( - 1 ) - 305}{2 \cdot 1} : \frac{1 - 305}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 305}{2}, x = \frac{1 - 305}{2}

\frac{i}{1 + i}

x - \frac{x}{3} + \frac{39}{8} = \frac{x}{4} - \frac{2 x}{6}

1 > 100 \cdot \frac{( \frac{9}{10} ) ^{n}}{( \frac{9}{10} ) ^{1}}

5 x - 4 = 2 (x - 2)

x^{3} - 8 x^{2} + 2 x - 16

What are the solutions to the equation (x+8)(x-9)=4 ?
The solutions to the equation (x+8)(x-9)=4 are x=(1+sqrt(305))/2 ,x=(1-sqrt(305))/2
Find the zeros of (x+8)(x-9)=4
The zeros of (x+8)(x-9)=4 are x=(1+sqrt(305))/2 ,x=(1-sqrt(305))/2