What is ((8+2i)-(1-i))/((2+i)^2) ?

The solution to ((8+2i)-(1-i))/((2+i)^2) is (7+3i)/((2+i)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((8+2i)-(1-i))/((2+i)^2)

simplify

\frac{( 8 + 2 i ) - ( 1 - i )}{( 2 + i ) ^{2}}

\frac{7 + 3 i}{( 2 + i ) ^{2}}

Solution steps

\frac{( 8 + 2 i ) - ( 1 - i )}{( 2 + i ) ^{2}}

Apply rule:

(a) = a

(8 + 2 i) = 8 + 2 i

= \frac{8 + 2 i - ( 1 - i )}{( 2 + i ) ^{2}}

Simplify

8 + 2 i - (1 - i) : 3 i + 7

= \frac{3 i + 7}{( 2 + i ) ^{2}}

Rewrite in standard complex form:

\frac{7 + 3 i}{( 2 + i ) ^{2}}

= \frac{7 + 3 i}{( 2 + i ) ^{2}}

12 x^{2} + 5 x - 3

\frac{3 π}{2} \cdot \frac{180}{π}

\frac{12}{5} + \frac{4}{7} = \frac{4}{5} + \frac{3}{8}

\frac{- 1}{- 4}

\frac{a}{4} + 5 = \frac{5}{2}

What is ((8+2i)-(1-i))/((2+i)^2) ?
The solution to ((8+2i)-(1-i))/((2+i)^2) is (7+3i)/((2+i)^2)