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Popular >

|2x+1|+1<= 6

Solution

∣ 2 x + 1 ∣ + 1 \leq 6

Solution

- 3 \leq x \leq 2

+1

Interval Notation

[- 3, 2]

Solution steps

∣ 2 x + 1 ∣ + 1 \leq 6

Move

1

to the right side

∣ 2 x + 1 ∣ \leq 5

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 5 \leq 2 x + 1 \leq 5

2 x + 1 \geq - 5 and 2 x + 1 \leq 5

x \geq - 3 and x \leq 2

Merge Overlapping Intervals

- 3 \leq x \leq 2

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12 x^{2} + 5 x - 3

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\frac{3 π}{2} \cdot \frac{180}{π}

12/5+4/7 = 4/5+3/8

\frac{12}{5} + \frac{4}{7} = \frac{4}{5} + \frac{3}{8}

Frequently Asked Questions (FAQ)

What is |2x+1|+1<= 6 ?
The solution to |2x+1|+1<= 6 is -3<= x<= 2