What are the solutions to the equation (3x-4)^2=36 ?

The solutions to the equation (3x-4)^2=36 are x= 10/3 ,x=-2/3

Find the zeros of (3x-4)^2=36

The zeros of (3x-4)^2=36 are x= 10/3 ,x=-2/3

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(3 x - 4)^{2} = 36

x = \frac{10}{3}, x = - \frac{2}{3}

Decimal Notation

x = 3.33333 \dots, x = - 0.66666 \dots

Solution steps

(3 x - 4)^{2} = 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x - 4 = 36 : x = \frac{10}{3}

Solve

3 x - 4 = - 36 : x = - \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{10}{3}, x = - \frac{2}{3}

v^{2} + 11 v - 26 = 0

159

\frac{1}{2} x + 8 \leq 10

∣ 2 x + 1 ∣ + 1 \leq 6

\frac{3}{2} y - 1 = 11

What are the solutions to the equation (3x-4)^2=36 ?
The solutions to the equation (3x-4)^2=36 are x= 10/3 ,x=-2/3
Find the zeros of (3x-4)^2=36
The zeros of (3x-4)^2=36 are x= 10/3 ,x=-2/3