What are the solutions to the equation 9r^2-12r+4=0 ?

The solutions to the equation 9r^2-12r+4=0 are r= 2/3

Find the zeros of 9r^2-12r+4=0

The zeros of 9r^2-12r+4=0 are r= 2/3

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9 r^{2} - 12 r + 4 = 0

r = \frac{2}{3}

Decimal Notation

r = 0.66666 \dots

Solution steps

9 r^{2} - 12 r + 4 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 4 = 0

r_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 9}

r = \frac{- ( - 12 )}{2 \cdot 9}

\frac{- ( - 12 )}{2 \cdot 9} = \frac{2}{3}

r = \frac{2}{3}

The solution to the quadratic equation is:

r = \frac{2}{3}

6. 5^{2}

(\frac{8}{5})^{2}

3 k^{3} - 4 k^{2} - 12 k + 16

- 2 = \frac{7}{5} (7) + b

4 - p < p + 7

What are the solutions to the equation 9r^2-12r+4=0 ?
The solutions to the equation 9r^2-12r+4=0 are r= 2/3
Find the zeros of 9r^2-12r+4=0
The zeros of 9r^2-12r+4=0 are r= 2/3