What are the solutions to the equation 4p^2+3=4p ?

The solutions to the equation 4p^2+3=4p are p= 1/2+i(sqrt(2))/2 ,p= 1/2-i(sqrt(2))/2

Find the zeros of 4p^2+3=4p

The zeros of 4p^2+3=4p are p= 1/2+i(sqrt(2))/2 ,p= 1/2-i(sqrt(2))/2

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4 p^{2} + 3 = 4 p

p = \frac{1}{2} + i \frac{2}{2}, p = \frac{1}{2} - i \frac{2}{2}

Solution steps

4 p^{2} + 3 = 4 p

Move

4 p

to the left side

4 p^{2} + 3 - 4 p = 0

Write in the standard form

a x^{2} + b x + c = 0

4 p^{2} - 4 p + 3 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

Simplify

(- 4)^{2} - 4 \cdot 4 \cdot 3 : 42 i

p_{1, 2} = \frac{- ( - 4 ) \pm 4 2 i}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 4}, p_{2} = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 4}

p = \frac{- ( - 4 ) + 4 2 i}{2 \cdot 4} : \frac{1}{2} + i \frac{2}{2}

p = \frac{- ( - 4 ) - 4 2 i}{2 \cdot 4} : \frac{1}{2} - i \frac{2}{2}

The solutions to the quadratic equation are:

p = \frac{1}{2} + i \frac{2}{2}, p = \frac{1}{2} - i \frac{2}{2}

7^{2}

9 x^{2} - 12 x > - 4

\frac{2}{5} (10)

z - 7 z = 9 z - 9 - z

2 j^{2} + 5 j + 2

What are the solutions to the equation 4p^2+3=4p ?
The solutions to the equation 4p^2+3=4p are p= 1/2+i(sqrt(2))/2 ,p= 1/2-i(sqrt(2))/2
Find the zeros of 4p^2+3=4p
The zeros of 4p^2+3=4p are p= 1/2+i(sqrt(2))/2 ,p= 1/2-i(sqrt(2))/2