What is ((2-3x))/((x+2)(3-x))<= 0 ?

The solution to ((2-3x))/((x+2)(3-x))<= 0 is x<-2\lor 2/3 <= x<3

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((2-3x))/((x+2)(3-x))<= 0

\frac{( 2 - 3 x )}{( x + 2 ) ( 3 - x )} \leq 0

x < - 2 or \frac{2}{3} \leq x < 3

Interval Notation

(- \infty, - 2) \cup [\frac{2}{3}, 3)

Decimal Notation

x < - 2 or 0.66666 \dots \leq x < 3

Solution steps

\frac{2 - 3 x}{( x + 2 ) ( 3 - x )} \leq 0

Identify the intervals

x < - 2 or \frac{2}{3} \leq x < 3

\frac{( - \frac{1}{3} ) - 1}{2 ( - \frac{1}{3} ) ^{2} - ( - \frac{1}{3} )}

(\frac{1}{2})^{12}

7 (2 x - 1) = 5 (x + 6) - 13

4 p^{2} + 3 = 4 p

7^{2}

What is ((2-3x))/((x+2)(3-x))<= 0 ?
The solution to ((2-3x))/((x+2)(3-x))<= 0 is x<-2\lor 2/3 <= x<3