What are the solutions to the equation (w+1)^2=20 ?

The solutions to the equation (w+1)^2=20 are w=2sqrt(5)-1,w=-2sqrt(5)-1

Find the zeros of (w+1)^2=20

The zeros of (w+1)^2=20 are w=2sqrt(5)-1,w=-2sqrt(5)-1

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(w + 1)^{2} = 20

w = 25 - 1, w = - 25 - 1

Decimal Notation

w = 3.47213 \dots, w = - 5.47213 \dots

Solution steps

(w + 1)^{2} = 20

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

w + 1 = 20 : w = 25 - 1

Solve

w + 1 = - 20 : w = - 25 - 1

The solutions to the quadratic equation are:

w = 25 - 1, w = - 25 - 1

u^{2} + 13 = 0

\frac{1}{x} \leq x

\frac{5 n}{30 m} + \frac{2 m + 4 n}{30 m}

\frac{11}{6} + \frac{9}{2}

∣ 2 g - 5 ∣ \geq 9

What are the solutions to the equation (w+1)^2=20 ?
The solutions to the equation (w+1)^2=20 are w=2sqrt(5)-1,w=-2sqrt(5)-1
Find the zeros of (w+1)^2=20
The zeros of (w+1)^2=20 are w=2sqrt(5)-1,w=-2sqrt(5)-1