What is 5x^{1/2}*2x^{-5/3} ?

The solution to 5x^{1/2}*2x^{-5/3} is (10)/(x^{7/6)}

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simplify 5x^{1/2}*2x^{-5/3}

simplify

5 x^{\frac{1}{2}} \cdot 2 x^{- \frac{5}{3}}

\frac{10}{x ^{\frac{7}{6}}}

Solution steps

5 x^{\frac{1}{2}} \cdot 2 x^{- \frac{5}{3}}

Multiply the numbers:

5 \cdot 2 = 10

= 10 x^{\frac{1}{2}} x^{- \frac{5}{3}}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{\frac{1}{2}} x^{- \frac{5}{3}} = x^{\frac{1}{2} - \frac{5}{3}}

= 10 x^{\frac{1}{2} - \frac{5}{3}}

\frac{1}{2} - \frac{5}{3} = - \frac{7}{6}

= 10 x^{- \frac{7}{6}}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- \frac{7}{6}} = \frac{1}{x ^{\frac{7}{6}}}

= 10 \cdot \frac{1}{x ^{\frac{7}{6}}}

Simplify

10 \cdot \frac{1}{x ^{\frac{7}{6}}} : \frac{10}{x ^{\frac{7}{6}}}

= \frac{10}{x ^{\frac{7}{6}}}

m^{2} = 64

8^{2} + 8^{2}

10 x^{2} + 19 x + 7

(9 x + 3)^{2} - 10 (9 x + 3) - 144 = 0

(w + 1)^{2} = 20

What is 5x^{1/2}*2x^{-5/3} ?
The solution to 5x^{1/2}*2x^{-5/3} is (10)/(x^{7/6)}