What is factor a^5+b^5c^5 ?

The solution to factor a^5+b^5c^5 is (a+bc)(a^4-a^3bc+a^2b^2c^2-ab^3c^3+b^4c^4)

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factor a^5+b^5c^5

factor

a^{5} + b^{5} c^{5}

(a + b c) (a^{4} - a^{3} b c + a^{2} b^{2} c^{2} - a b^{3} c^{3} + b^{4} c^{4})

Solution steps

a^{5} + b^{5} c^{5}

Rewrite

b^{5} c^{5}

(b c)^{5}

= a^{5} + (b c)^{5}

Apply factoring rule:

x^{n} + y^{n} = (x + y) (x^{n - 1} - x^{n - 2} y + \dots - x y^{n - 2} + y^{n - 1})

n is odd

a^{5} + (b c)^{5} = (a + b c) (a^{4} - a^{3} b c + a^{2} (b c)^{2} - a (b c)^{3} + (b c)^{4})

= (a + b c) (a^{4} - a^{3} b c + a^{2} (b c)^{2} - a (b c)^{3} + (b c)^{4})

Simplify

(a + b c) (a^{4} - a^{3} b c + a^{2} (b c)^{2} - a (b c)^{3} + (b c)^{4}) : (a + b c) (a^{4} - a^{3} b c + a^{2} b^{2} c^{2} - a b^{3} c^{3} + b^{4} c^{4})

= (a + b c) (a^{4} - a^{3} b c + a^{2} b^{2} c^{2} - a b^{3} c^{3} + b^{4} c^{4})

2 (x + 8) = 26

\frac{5 ^{5} e ^{- 5}}{5 !}

2 y^{2} + 11 y + 10 = 0

x^{2} - x + 14 = 0

\frac{1}{9} - 1

What is factor a^5+b^5c^5 ?
The solution to factor a^5+b^5c^5 is (a+bc)(a^4-a^3bc+a^2b^2c^2-ab^3c^3+b^4c^4)