What are the solutions to the equation 9y^2+6y-8=0 ?

The solutions to the equation 9y^2+6y-8=0 are y= 2/3 ,y=-4/3

Find the zeros of 9y^2+6y-8=0

The zeros of 9y^2+6y-8=0 are y= 2/3 ,y=-4/3

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9 y^{2} + 6 y - 8 = 0

y = \frac{2}{3}, y = - \frac{4}{3}

Decimal Notation

y = 0.66666 \dots, y = - 1.33333 \dots

Solution steps

9 y^{2} + 6 y - 8 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 ( - 8 )}{2 \cdot 9}

6^{2} - 4 \cdot 9 (- 8) = 18

y_{1, 2} = \frac{- 6 \pm 18}{2 \cdot 9}

Separate the solutions

y_{1} = \frac{- 6 + 18}{2 \cdot 9}, y_{2} = \frac{- 6 - 18}{2 \cdot 9}

y = \frac{- 6 + 18}{2 \cdot 9} : \frac{2}{3}

y = \frac{- 6 - 18}{2 \cdot 9} : - \frac{4}{3}

The solutions to the quadratic equation are:

y = \frac{2}{3}, y = - \frac{4}{3}

x^{2} + 3 x = 24

\frac{15 d ^{- 9} t ^{4}}{( 5 d ^{- 3} t ) ^{- 2}}

7 - \frac{2}{3} x < x - 8

\frac{( 4 ) ( 59.58 \cdot 1 0 ^{- 6} )}{π}

\frac{202}{210} + \frac{11}{3}

What are the solutions to the equation 9y^2+6y-8=0 ?
The solutions to the equation 9y^2+6y-8=0 are y= 2/3 ,y=-4/3
Find the zeros of 9y^2+6y-8=0
The zeros of 9y^2+6y-8=0 are y= 2/3 ,y=-4/3