What are the solutions to the equation 3x^2=8 ?

The solutions to the equation 3x^2=8 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))

Find the zeros of 3x^2=8

The zeros of 3x^2=8 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 x^{2} = 8

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

Decimal Notation

x = 1.63299 \dots, x = - 1.63299 \dots

Solution steps

3 x^{2} = 8

Divide both sides by

3

x^{2} = \frac{8}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{8}{3}, x = - \frac{8}{3}

\frac{8}{3} = \frac{2 2}{3}

- \frac{8}{3} = - \frac{2 2}{3}

x = \frac{2 2}{3}, x = - \frac{2 2}{3}

\frac{- 3 + 5}{2}

∣ x - 6 ∣ = - 5

3 \leq \frac{2 x - 3}{5} < 7

5 x - 9 = 2 x + 18

\frac{x ^{2} - x - 2}{x ^{2} + 4 x + 3} \leq 0

What are the solutions to the equation 3x^2=8 ?
The solutions to the equation 3x^2=8 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))
Find the zeros of 3x^2=8
The zeros of 3x^2=8 are x=(2sqrt(2))/(sqrt(3)),x=-(2sqrt(2))/(sqrt(3))