What are the solutions to the equation (7k-1)^2=-8 ?

The solutions to the equation (7k-1)^2=-8 are k= 1/7+i(2sqrt(2))/7 ,k= 1/7-i(2sqrt(2))/7

Find the zeros of (7k-1)^2=-8

The zeros of (7k-1)^2=-8 are k= 1/7+i(2sqrt(2))/7 ,k= 1/7-i(2sqrt(2))/7

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(7 k - 1)^{2} = - 8

k = \frac{1}{7} + i \frac{2 2}{7}, k = \frac{1}{7} - i \frac{2 2}{7}

Solution steps

(7 k - 1)^{2} = - 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

7 k - 1 = - 8 : k = \frac{1}{7} + i \frac{2 2}{7}

Solve

7 k - 1 = - - 8 : k = \frac{1}{7} - i \frac{2 2}{7}

The solutions to the quadratic equation are:

k = \frac{1}{7} + i \frac{2 2}{7}, k = \frac{1}{7} - i \frac{2 2}{7}

4 x^{4} - 7 x^{2} + 3

0.5 x = 1 - x^{2}

c d + 5 c + 4 d + 20

C a + H Cl

\frac{x}{12} - 1 = - 6

What are the solutions to the equation (7k-1)^2=-8 ?
The solutions to the equation (7k-1)^2=-8 are k= 1/7+i(2sqrt(2))/7 ,k= 1/7-i(2sqrt(2))/7
Find the zeros of (7k-1)^2=-8
The zeros of (7k-1)^2=-8 are k= 1/7+i(2sqrt(2))/7 ,k= 1/7-i(2sqrt(2))/7