What is ((3x^5y^4z)/(x^0y^{-3)z})^2 ?

The solution to ((3x^5y^4z)/(x^0y^{-3)z})^2 is 9x^{10}y^{14}

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simplify ((3x^5y^4z)/(x^0y^{-3)z})^2

simplify

(\frac{3 x ^{5} y ^{4} z}{x ^{0} y ^{- 3} z})^{2}

9 x^{10} y^{14}

Solution steps

(\frac{3 x ^{5} y ^{4} z}{x ^{0} y ^{- 3} z})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 3 x ^{5} y ^{4} z ) ^{2}}{( x ^{0} y ^{- 3} z ) ^{2}}

Simplify

(3 x^{5} y^{4} z)^{2} : 9 x^{10} y^{8} z^{2}

= \frac{9 x ^{10} y ^{8} z ^{2}}{( x ^{0} y ^{- 3} z ) ^{2}}

Simplify

(x^{0} y^{- 3} z)^{2} : \frac{z ^{2}}{y ^{6}}

= \frac{9 x ^{10} y ^{8} z ^{2}}{\frac{z ^{2}}{y ^{6}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{9 x ^{10} y ^{8} z ^{2} y ^{6}}{z ^{2}}

Cancel the common factor:

z^{2}

= 9 x^{10} y^{8} y^{6}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

y^{8} y^{6} = y^{8 + 6}

= 9 x^{10} y^{8 + 6}

Add the numbers:

8 + 6 = 14

= 9 x^{10} y^{14}

\frac{1}{3} (9)

7 (6 x - 3) - 6 x < 6 (1 + 6 x) - 15

54 x^{3} - 16 y^{3}

x - 0.02 x = 76.44

- 9 x - 1 = - 8 x + 15

What is ((3x^5y^4z)/(x^0y^{-3)z})^2 ?
The solution to ((3x^5y^4z)/(x^0y^{-3)z})^2 is 9x^{10}y^{14}