What are the solutions to the equation x^2+2x+1=0 ?

The solutions to the equation x^2+2x+1=0 are x=-1

Find the zeros of x^2+2x+1=0

The zeros of x^2+2x+1=0 are x=-1

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x^{2} + 2 x + 1 = 0

x = - 1

Solution steps

x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

x = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

\frac{3}{2 \frac{2}{3}}

63 + 45 b

x^{4} + 6 x^{2} + 9

(- 36)^{\frac{5}{2}}

12 c^{2} - 20 d^{2}

What are the solutions to the equation x^2+2x+1=0 ?
The solutions to the equation x^2+2x+1=0 are x=-1
Find the zeros of x^2+2x+1=0
The zeros of x^2+2x+1=0 are x=-1